Question

by grouping
x³-x²-xy+x+y-1

​

Answer 1

Given to factorise:-

${x}^{3} - {x}^{2} - xy + x + y -1$

Solution:-

${x}^{3} - {x}^{2} - xy + x + y - 1$

$= {x}^{2} (x - 1) - x(y - 1) + 1(y - 1)$

$= {x}^{2} (x - 1) - (1 - x)(y - 1)$

$= {x}^{2} (x - 1) + (x - 1)(y - 1)$

$= (x - 1)( {x}^{2} + y - 1)$

Answer:-

$(x - 1)( {x}^{2} + y - 1)$