Question

By how many percent the power in a lamp decreased

Answer 1

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Answer 2

Answer:m1 = 2kg

m2= 3kg

Now,

T= (2m1 × m2 / m1 × m2 )g

= (2 ×2 ×3/ 2+3 )g

= 12/5 g

a = (m2 - m1 / m1+ m2) g

= (3-2/3+2)g

= g/5

Explanation: