Question

By how much 6÷7/8 exceeds 6/7÷8

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

6÷7/8 exceeds 6/7÷8 by $5 \frac{1}{28}$

Step-by-step explanation:

Given two terms are

$6 \div \frac{7}{8} \\ = 6 \times \frac{8}{7} \\ = \frac{48}{7}$

and

$\frac{6}{7} \div 8 \\ = \frac{6}{7} \times \frac{1}{8} \\ = \frac{3}{28}$

Now we want to find by how much $\frac{48}{7}$ exceeds $\frac{3}{28}$

We know, x exceeds y by $(x - y)$

So,$\frac{48}{7}$ exceeds $\frac{3}{28}$ by

$( \frac{48}{7} - \frac{3}{28} ) \\ = \frac{48 \times 4 - 3}{28} \\ = \frac{141}{28} \\ = 5 \frac{1}{28}$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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