Question

by how much does 1÷(10/11) exceeds (1/10)÷11​

Answer 1

Step-by-step explanation:

1÷(10/11)=1*(11/10)

(1/10)÷11=(1/10)*1/11

1/110+x=11/10

x=11/10-1/110

x=11*11-1/110

x=121-1/110

x=120\110

X=12/11

Answer 2

Answer:

$1\div(\frac{10}{11})$ exceeds $(\frac{1}{10})\div 11+x$ by $\frac{12}{11}$    

Step-by-step explanation:

To find : By how much does $1\div(\frac{10}{11})$ exceeds $(\frac{1}{10})\div 11+x$?

Solution :

Let x be the number which exceeds.

According to question,

$1\div(\frac{10}{11})=(\frac{1}{10})\div 11+x$

$\frac{11}{10}=\frac{1}{10\times11}+x$

$\frac{11}{10}=\frac{1}{110}+x$

$x=\frac{11}{10}-\frac{1}{110}$

$x=\frac{121-1}{110}$

$x=\frac{120}{110}$

$x=\frac{12}{11}$

Therefore, $1\div(\frac{10}{11})$ exceeds $(\frac{1}{10})\div 11+x$ by $\frac{12}{11}$