Math, asked by kailasdeore11, 2 months ago

by how much does √12 +√18 exceed √3+√2​

Answers

Answered by harshit4verma2005
1

Answer:

(√12+√18) -(√3+√2)

2√3+3√2−√3–√2  

=√3+2√2

Answered by Anonymous
3

Answer: Exceeds by (2√3 + √3).

Explanation:

We can describe √12 + √18 in terms of √3 and √2,

√12 + √18 = 2√3 + 3√2.

Now,

(2√3 + 3√2) - (√3 + √2)

= 2√3 - √3 + 3√2 - √2

= 1√3 + 2√2

= 2√2 + √3.

Therefore, (√12 + √18) exceed (√3 + √2) by (2√3 + √3).

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