by how much does √12 +√18 exceed √3+√2
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Answered by
1
Answer:
(√12+√18) -(√3+√2)
2√3+3√2−√3–√2
=√3+2√2
Answered by
3
Answer: Exceeds by (2√3 + √3).
Explanation:
We can describe √12 + √18 in terms of √3 and √2,
√12 + √18 = 2√3 + 3√2.
Now,
(2√3 + 3√2) - (√3 + √2)
= 2√3 - √3 + 3√2 - √2
= 1√3 + 2√2
= 2√2 + √3.
Therefore, (√12 + √18) exceed (√3 + √2) by (2√3 + √3).
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