By how much does 18 -3p -11a +5pq - 2pq^2 + 5qp^2 exceed -5pq^2+4p^2q-3pq-8p+7q-10?
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what a big question..........
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Subtracting 4p2q−3pq+5pq2−8p+7q−10 from 18−3p−11q+5pq−2pq2+5p2q, we have
= (18−3p−11q+5pq−2pq2+5p2q)−(4p2q−3pq+5pq2−8p+7q−10)
= 18−3p−11q+5pq−2pq2+5p2q−7p2q+3pq−5pq2+8p−7q+10
= 28+5p−78q+8pq−7pq2+p2q
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