Question

by How much does √27+√18 exceed √3+√2?

Answer 1

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Answer 2

√27 + √18 = √(9×3) + √(9×2)
= 3√3 + 3√2
= 3(√3 + √2 )
Hence (√27 + √18) exceeds (√3 +√2) by 3 times