Question

By how much does 3x²-5x+6 exceed x³-x²+4x-1
​

Answer 1

Answer:

$-x^3 +4x^2 -9x +7$

Step-by-step explanation:

By how much does 3x²-5x+6 exceed x³-x²+4x-1

​So we have to subtract$3x^{2} -5x + 6 - (x^3 - x^2 +4x-1)$ x³-x²+4x-1  from 3x²-5x+6

As there is a sign of - before bracket so on opening bracket sign inside bracket will get change$= 3x^{2} -5x + 6 - x^3 + x^2 - 4x + 1\\= -x^3 +4x^2 -9x +7$

Answer 2

Hey there.....Here is your answer

(3x^2 - 5x + 6) - (x^3 - x^2 + 4x - 1)

= 3x^2 - 5x + 6 - x^3 + x^2 - 4x + 1

= - x^3 + 4x^2 - 9x + 7


Therefore 3x²-5x+6 exceeds x³-x²+4x-1 by - x^3 + 4x^2 - 9x + 7


Hope this helps you friend

Be brainly