by how much does 8x³-6x²+5x-10 exceed 4x³+2x²+7x-3
Answers
Answered by
1
Answer:
8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x – 3
= (8x3 – 6x2 + 9x – 10) – (4x3 + 2x2 + 7x – 3)
= 8x3 – 6x2 + 9x – 10 – 4x3 – 2x2 – 7x + 13
= 8x3 – 4x3 – 6x2 – 2x2 + 9x – 7x – 10 + 3
= 4x3 – 8x2 + 2x – 7
Answered by
1
hope it helps you!
please mark me as a brainliest
Attachments:

Similar questions