By
how much does 8xcube-6xsquare+9x-10 exceed 4xcube+2xsquare+7x-3
its urgent who ever will sendwill be marked as brainliest
plz send the explanation also
Answers
Answered by
1
Answer:
4x3 – 8x2 + 2x – 7
Step-by-step explanation:
8x3 – 6x2 + 9x – 10 exceeds 4x3 + 2x2 + 7x – 3
= (8x3 – 6x2 + 9x – 10) – (4x3 + 2x2 + 7x – 3)
= 8x3 – 6x2 + 9x – 10 – 4x3 – 2x2 – 7x + 13
= 8x3 – 4x3 – 6x2 – 2x2 + 9x – 7x – 10 + 3
= 4x3 – 8x2 + 2x – 7
Answered by
0
Answer:
4x³ - 8x² + 2x - 7
Step-by-step explanation:
(8x³ - 6x² + 9x - 10) - (4x³ + 2x² + 7x - 3)
8x³ - 6x² + 9x - 10 - 4x³ - 2x² - 7x + 3
4x³ - 8x² + 2x - 7
Hope it helps, pls mark it as the BRAINLIEST and pls follow me
Similar questions