by how much does x square-2ax +5 exceed 3x square -5x+6?
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Answer:
9x^2 -5x + 2ax +1
Step-by-step explanation:
(3x) ^2 -5x +6 -( - 2ax +5)
9x ^2 -5x +6 + 2ax -5
9 X ^2 -5x + 2ax +1
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