By how much is 1 greater than 7x−2y+3?
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Answered by
1
given 2x+3y=7 ... (i)
and 3x+2y=3 ..(ii)
On subtracting (ii) from (i) we get
2x+3y−3x−2y=7−3
⟹−x+y=4
⟹x−y=−4
HENCE, the answer is −4.
Answered by
2
7x - 2y + 3
7x - 2y = - 3
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