Math, asked by pranavkoduru964, 9 months ago

by how much is a^2-2ab-b^2more than 2a^2+2sb+2b^2​

Answers

Answered by reshamsaha99
0

(a²-2ab-b²)-(2a²+2ab+2b²)

=a²-2ab-b²-2a²-2ab-2b²

=a²-2a²-2ab-2ab-b²-2b²

= -a²-4ab-3b²

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Answered by vikashpatnaik2009
0

Answer:

The value of  

​  

 

1+a  

2

−b  

2

 

2ab

2b

​  

 

2ab

1−a  

2

+b  

2

 

−2a

​  

 

−2b

2a

1−a  

2

−b  

2

 

​  

 

​  

 is

C  

1

​  

→C  

1

​  

−bC  

3

​  

,C  

2

​  

→C  

2

​  

+aC  

3

​  

 

=  

​  

 

1+a  

2

+b  

2

 

0

b(1+a  

2

+b  

2

)

​  

 

0

1+a  

2

+b  

2

 

−a(1+b  

2

+a  

2

)

​  

 

−2b

2a

1−a  

2

−b  

2

 

​  

 

​  

 

=(1+a  

2

+b  

2

)  

2

 

​  

 

1

0

b

​  

 

0

1

−a

​  

 

−2b

2a

1−a  

2

−b  

2

 

​  

 

​  

 

=(1+a  

2

+b  

2

)  

2

{(1−a  

2

−b  

2

+2a  

2

)+2b  

2

}  

=(1+a  

2

+b  

2

)  

3

 

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