Math, asked by rajeevranjankumar729, 7 months ago

by how much is sum of a⁴-6a²b²+b⁴ and -2a⁴+5a²b²+3b⁴ greater than -a⁴-a²b²-4b⁴​

Answers

Answered by dtejeswini
4

Answer:

sum of those two is -1a^4-1a^2b^2+4b^4.

this sum is greater than (-a^4 -a^2b^2-4b^4)by+8b^4

therefore answer is 8b^4

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