Math, asked by rajeevranjankumar729, 6 months ago

by how much is sum of a⁴-6a²b²+b⁴ and -2a⁴+5a²b²+3b⁴ greater than -a⁴-a²b²-4b⁴​

Answers

Answered by anjanakurup728
3

a⁴-6a²b²+b⁴ + ( - 2a⁴+5a²b²+3b⁴)

= a⁴-6a²b²+b⁴ - 2a⁴+ 5a²b² +3b⁴

= -a⁴- a²b² + 4b⁴

Difference = -a⁴- a²b² + 4 b⁴ - (-a⁴-a²b²-4b⁴)

Difference = -a⁴- a²b² + 4 b⁴ + a⁴+a²b²+ 4b ⁴

Difference = 8 b⁴

So, sum of a⁴-6a²b²+b⁴ and -2a⁴+5a²b²+3b⁴ greater than -a⁴-a²b²-4b⁴ by 8b⁴

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