by how much is the average of the natural numbers from 1 to 50 more than the average of the natural numbers from 1to 25???
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Answered by
17
average of n natural numbers = n+1/2
= 50+1/2
= 25.5
average of n natural numbers = n+1/2
= 25+1/2
= 13
difference between 1st average and 2nd average = 25.5 - 13 = 12.5
= 50+1/2
= 25.5
average of n natural numbers = n+1/2
= 25+1/2
= 13
difference between 1st average and 2nd average = 25.5 - 13 = 12.5
Answered by
2
12.5 is the correct answer
Hope it helps..
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