Question

by how much is the sum of a- 5 a- 2 and a^2+ 6a + 7 is greater than - a^2 - 2a + 1​

Answer 1

Answer:

$<marquee>Refer to the attachment :)$

let the number be A

$a - 5 + a - 2 + {a}^2 + 6a + 7 + A = -{a}^2 - 2a + 1$

${a}^2 + 8a + A = -{a}^2 - 2a + 1$

$A = -{a}^2 - 2a + 1 - {a}^2 - 8a$

$A = - 2{a}^2 - 10 a + 1$

by SDM

$A = - 2{a}^2 - 10 a + 1$

the value of a = 5 + 3√3 and 5 - 3√3

by puttimg both these value u will get value of A

Answer 2

Step-by-step explanation:

hope it is helpful for you