:By how much is the sum of a4–6a2b2+b4and –2a4+5a2b2+3b4greater than –a4–a2b2–4b4
Answers
Answered by
0
Answer:
[a4–6a2b2+b4 +(–2a4+5a2b2+3b4)] - (–a4–a2b2–4b4)
= (-3a4-a2b2+4b4) - (-a4-a2b2-4b4)
= -3a4+a4-a2b2+a2b2+4b4+4b4
= -2a4 + 8b4.
Similar questions