Math, asked by nehadang11, 2 months ago

By how much is the sum of a4–6a2b2+b4and –2a4+5a2b2+3b4greater than –a4–a2b2–4b4

Answers

Answered by verdanish63

1

Answer:

[a4–6a2b2+b4 +(–2a4+5a2b2+3b4)] - (–a4–a2b2–4b4)

= (-3a4-a2b2+4b4) - (-a4-a2b2-4b4)

= -3a4+a4-a2b2+a2b2+4b4+4b4

= -2a4 + 8b4.

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