Question

by how much must (5a^2b^2-2ab+3a^2-b^2) be increased to get (6a^2b^2-3ab+4a^2-2b^2)

Answer 1

Answer:

a^2b^2-ab+a^2-b^2

Step-by-step explanation:

(6a^2b^2-3ab+4a^2-2b^2) – (5a^2b^2-2ab+3a^2-b^2) = a^2b^2-ab+a^2-b^2