Question

By increasing temperature of a gas by 6 c its pressure increases by 0.4% at constant volume. find initial temperature of gas

Answer 1

Answer:

Step-by-step explanation: According to the question the volume remains constant i.e. an isochoric reaction

By law,

P¹V¹/T¹ = P²V²/T²

=> T¹/P¹ = T²/P² or P¹/T¹ = P²/ T²

Then follow the following :

Answer 2

Dear Student,

◆ Answer -

Initial temperature of gas = 1227 °C

● Explanation -

We know that,

P ∝ T

So,

∆P/P = ∆T/T

0.4/100 = 6/T

T = 6 × 100 / 0.4

T = 1500 K

T = 1500 - 273 °C

T = 1227 °C

Hence, the initial temperature of the gas is 1227 °C.

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