By increasing temperature of a gas by 6 c its pressure increases by 0.4% at constant volume. find initial temperature of gas
Answers
Answered by
14
Answer:
Step-by-step explanation: According to the question the volume remains constant i.e. an isochoric reaction
By law,
P¹V¹/T¹ = P²V²/T²
=> T¹/P¹ = T²/P² or P¹/T¹ = P²/ T²
Then follow the following :
Attachments:
Answered by
4
Dear Student,
◆ Answer -
Initial temperature of gas = 1227 °C
● Explanation -
We know that,
P ∝ T
So,
∆P/P = ∆T/T
0.4/100 = 6/T
T = 6 × 100 / 0.4
T = 1500 K
T = 1500 - 273 °C
T = 1227 °C
Hence, the initial temperature of the gas is 1227 °C.
Thanks dear for asking. Hope this is helpful to you...
Similar questions