Question

By increasing temperature of a gas by 6 c its pressure increases by 0.4% at constant volume. find initial temperature of gas

Answer 1

from ideal gas law, for specific amount of gas , pressure of gas be directly proportional to its temperature at constant volume .
e.g., $P\propto T$
so, $\frac{P_1}{P_2}=\frac{T_1}{T_2}$

or, $\frac{P_2}{P_1}=\frac{T_2}{T_1}$

or, $\frac{P_2-P_1}{P_1}=\frac{T_2-T_1}{T_1}$

or, $\frac{P_2-P_1}{P_1}\times100=\frac{T_2-T_1}{T_1}\times100$

or, percentage change in pressure = change in temperature/initial temperature × 100

or, 0.4 = 6/$T_1$ × 100

or, $T_1$ = 600/0.4 = 1500°C

Answer 2

Answer:

percentage change in pressure = change in temperature/initial temperature × 100

or, 0.4 = 6/T1 × 100

or, T1= 600/0.4 = 1500°C