Question

By inverse proportion solve--

10 cooks working for 8 hours each can prepare a meal for 536 people. How many cooks will be needed to prepare a meal for 737 people, if they are required to prepare a meal in 5 hours? ​

Answer 1

Gɪᴠᴇɴ :-

• 10 cooks working for 8 hours each can prepare a meal for 536 people.

Tᴏ Fɪɴᴅ :-

• How many cooks will be needed to prepare a meal for 737 people, if they are required to prepare a meal in 5 hours ?

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

➺ If M1 men can do W1 work working H1 hours per day and M2 men can do W2 work working H2 hours per day, then

❦❦ (M1*H1)/W1 = (M2*H2)/W2 ❦❦

( work is inversely proportion . )

Sᴏʟᴜᴛɪᴏɴ :-

we Have :-

➪ M1 = 10 cooks .

➪ H1 = 8 Hours.

➪ W1 = 536 People .

➪ M2 = X cooks . (Let).

➪ H2 = 5 Hours.

➪ W2 = 737 People.

Putting Values in formula we get :-

➪ (10 * 8) / 536 = (x * 5) / 737

➪ 10 * 8 * 737 = x * 5 * 536

➪ 16 * 737 = X * 536

➪ X = 22 Cooks . (Ans.)

Hence, 22 Cooks Prepare the food in Time.

Answer 2

Answer:

• $\rm Hour_1=8$
• $\rm Work_1=536$
• $\rm Cook_1=10$
• $\rm Hour_2=5$
• $\rm Work_2=737$
• $\rm Cook_2=?$

$\rule{120}{1}$

$\underline{\bigstar\:\boldsymbol{According\:to\:the\:Question :}}$

$:\implies\sf \dfrac{(MDH)_1}{W_1}=\dfrac{(MDH)_2}{W_2}\\\\\\:\implies\sf \dfrac{M_1 \times H_1}{W_1}=\dfrac{M_2 \times H_2}{W_2}\\\\\\:\implies\sf \dfrac{10 \times 8}{536} = \dfrac{M_2 \times 5}{737}\\\\\\:\implies\sf \dfrac{10 \times 8 \times 737}{536 \times 5} = M_2\\\\\\:\implies\sf \dfrac{10 \times 8 \times 67\times11}{8 \times 67 \times 5} = M_2\\\\\\:\implies\sf 2 \times 11 = M_2\\\\\\:\implies\underline{\boxed{\sf M_2 = 22}}$

⠀

$\therefore\:\underline{\textsf{\textbf{22 cooks} will be needed to prepare required meal.}}$