Question

by long division find the remainder when a polynomial 4x^4-6x^3+6x.^2-1\2x^2-3​

Answer 1

Let x=0.47ˉ  (Mixed recurring decimal)

i.e. x=0.47777…(1)

Multiplying (1) by 10, to make it pure recurring decimal, we get

10x=4.7777…(2)

Further multiplying (2) by 10, we get

100x=47.777….(3)

Subtracting (2) from (3), we get

100x–10x=(47.777…)–(4.7777…)

⇒90x=43

⇒x=9043

Thus 0.47ˉ=9043

Answer 2

Answer:

Let x=0.47 (Mixed recurring decimal)

i.e. x=0.47777...(1)

Multiplying (1) by 10, to make it pure recurring decimal, we get

10x=4.7777...(2)

Further multiplying (2) by 10, we get

100x=47.777....(3)

Subtracting (2) from (3), we get

100x-10x=(47.777...)-(4.7777...)

→ 90x=43

⇒x=9043

Thus 0.47 =9043

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Step-by-step explanation:

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