By long division method subtract the remainder by 1989
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remainder is 6
This is how I solved it:-
319897=(7−4)19897319897=(7−4)19897
Every term in the expansion of (7−4)1989(7−4)1989 would contain the number '7' except (−4)1989(−4)1989
So it ultimately reduces to finding the the remainder when (−4)1989(−4)1989 is divided by 7.
(−4)19897=(−1).(4)19897=(−1).(64)6637
This is how I solved it:-
319897=(7−4)19897319897=(7−4)19897
Every term in the expansion of (7−4)1989(7−4)1989 would contain the number '7' except (−4)1989(−4)1989
So it ultimately reduces to finding the the remainder when (−4)1989(−4)1989 is divided by 7.
(−4)19897=(−1).(4)19897=(−1).(64)6637
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