Question

By looking at the given graph .find the following a)ci ,cf and f for less than type b) ci ,cf and f for more than or equal type c) ci and f as a standard freqency table d) medain by graph method e) scalr fot the given graph f) verification of value of medain by formula method.​

Answer 1

Answer:

We are given the cumulative frequency distribution. So, we first construct a frequency table from the given cumulative frequency distribution and then we will make necessary computation to compute median.

Class intervals Frequency (f) Cumulative frequency (c.f.)

20-30 4 4

30-40 12 16

40-50 14 30

50-60 16 46

60-70 20 66

70-80 16 82

80-90 10 92

90-100 8 100

N=∑f

i

=100

Here, N=∑f

i

=100∴

2

N

=50

We observe that the cumulative frequency just greater than

2

N

=50 is 66 and the corresponding class is 60−70.

So, 60−70 is the median class.

∴l=60,f=20,F=46 and h=10

Now,

Median =l+

f

2

NN

−F×h⇒Median=60+ 20/50−46×10=62