By looking at the given graph .find the following a)ci ,cf and f for less than type b) ci ,cf and f for more than or equal type c) ci and f as a standard freqency table d) medain by graph method e) scalr fot the given graph f) verification of value of medain by formula method.
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Answer:
We are given the cumulative frequency distribution. So, we first construct a frequency table from the given cumulative frequency distribution and then we will make necessary computation to compute median.
Class intervals Frequency (f) Cumulative frequency (c.f.)
20-30 4 4
30-40 12 16
40-50 14 30
50-60 16 46
60-70 20 66
70-80 16 82
80-90 10 92
90-100 8 100
N=∑f
i
=100
Here, N=∑f
i
=100∴
2
N
=50
We observe that the cumulative frequency just greater than
2
N
=50 is 66 and the corresponding class is 60−70.
So, 60−70 is the median class.
∴l=60,f=20,F=46 and h=10
Now,
Median =l+
f
2
NN
−F×h⇒Median=60+ 20/50−46×10=62
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