Question

by means of an example, show that sin( a + b ) unequal to sin A + sin b​

Answer 1

Let A = 30° , B = 60°

i) sin(A+B)

= sin(30+60)

= sin90°

= 1 ------( 1 )

ii ) sinA + sinB

= sin30° + sin60°

= 1/2 + √3/2

= (1+√3)/2 ---( 2)

From (1) and (2) , we conclude

that ,

sin(A+B) ≠ sinA + sinB

••••

Answer 2

Answer:

take A=60;B=30

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