Question

by method of complete square

Answer 1

2x²+x-4= 0 where a= 2; b= 1 and c= -4
divide the equation by 2
x²+(x/2)-2 = 0
x² + (x/2) = 2
Now, add (b/2a)² = (1/4)² = 1/16


x²+(x/2)+(1/16) = 2+(1/16)
Now this forms an identity (a+b)² = a²+2ab+b²

[x+(1/4)]² = (33/16)

x+ (1/4) =( ✓33/✓16)
x+(1/4) = +(✓33/4) or - (✓33/4)

If x= (✓33/4)-(1/4) = (✓33-1)/4

If x = -(✓33/4)-(1/4) = -(✓33+1)/4

So, x= (✓33-1)/4. or. -(✓33+1)/4




hope this helps you

Answer 2

hey dude.....
ur answer is here.....!!!!!

thanks....!