Question

By mixing water a man gains the profit of 100 % . Find the quantity of water mixed by him.

Answer 1

Answer:

Step-by-step explanation:

Let cp of milk =c and of water is 0.

sp of mixed milk = c

cp of mixed milk = 0.9c

let qty of water and milk be n1 and n2 respectively.

By rule of allegation,

n1/n2=(c-0.9c)/(0.9c-0)

i.e. n1/n2= 1/9

So, ratio of milk to water is 9:1

Answer 2

Answer:

Step-by-step explanation:

He got 100% profit. This means that he sold the product for double the price. That means he sold 2 times the product. So he added the same quantity of the product there by multiplying the quantity

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Another way

Let m be the CP of the product and q be the quantity. Then total CP=mq

Suppose m liter of water added. Since he got 100% profit, the selling price was 2mq. So the total quantity sold=q+n

So (q+n)m=2mq

qm+nm=2mq

mq=mn

n=q

So same quantity of water is added