Question

By passing 0.1 Faraday of electricity through
ſused sodium chloride, the amount of chlorine
liberated is
1) 35.45 g
2) 70.9 g
3) 3.545 g
4) 17.77 g

Answer 1

Weight/equivalent wt = Q/ F

Eq weight= molwt / n Factor

Molwt of chlorine=35.5

In case of NaCl one electron is transferred from Na to CL so n Factor is 1

Eqwt=35.5/1=35.5

Weight=0.1F×35.5/F=0.1×35.5=3.55

Weight=3.545g

I hope this helps ( ╹▽╹ )

Answer 2

3.545g

Explanation:

uprokt abhikriya mein sodium chloride ke apghtn se 71g chlorine prapt hoti hai jisne 2 Faraday vidyut ki avashyakta hoti hai atah 0.1F vidyut se 3.545 g chlorine prapt hoti hai. 2NaCl=2Na+ &2Cl-