by picking a natural number randomly upto 1 to 100 , find the probability of being a perfect cube..... answer Quickly
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Answered by
1
S = ( 1,2,...,100)
let A be the event that no. is cube
A= ( 1, 8,27 64)
p(A) = n(A)/n(S)
= 4/100
= 1/25
let A be the event that no. is cube
A= ( 1, 8,27 64)
p(A) = n(A)/n(S)
= 4/100
= 1/25
devil6000:
27 also then answer is 4/100
Answered by
1
Hai friend, here is your answer. we know that, there are only 4perfect cubes between 1-100
1^3=1
2^3=8
3^3=27
4^3=64
so probability of getting a perfect cube by picking a natural numbers randomly is 4/100 =1/25=0.04
hope helped :)
1^3=1
2^3=8
3^3=27
4^3=64
so probability of getting a perfect cube by picking a natural numbers randomly is 4/100 =1/25=0.04
hope helped :)
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