Question

By placing a constant force f, the car moving at a speed of 15 meters per second can be stopped at 30 meters distance, if the speed of the car is 45 meters per second, then how much distance can it be prevented by the same force​

Answer 1

a=v−u2

where v is final velocity and u is initial velocity.

so (50−0)/5=10m/s2

d=vt+at22

v=0

a=10

t=5

therefore

d=0+0.5⋅10⋅52=125 meters