Question

By rationalizing the denominator of √3/(√7+√5)​

Answer 1

Answer:

$\frac{\sqrt{3}}{\sqrt{7} +\sqrt{5} } \\\\\frac{\sqrt{3}}{\sqrt{7} +\sqrt{5} } \times \frac{\sqrt{7} - \sqrt{5}}{\sqrt{7} -\sqrt{5} }\\\\\frac{\sqrt{3}(\sqrt{7} - \sqrt{5})}{(\sqrt{7}) ^{2} - (\sqrt{5}) ^{2}} \\\\\frac{\sqrt{3}(\sqrt{7} - \sqrt{5}) }{7 - 5} \\\\\frac{\sqrt{3}(\sqrt{7} - \sqrt{5}) }{2}\\\\\frac{\sqrt{21} - \sqrt{15} }{2}$

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