By reaction of c and o a mixture of co and co2 is obtained .What is the composition by mass of mixtyre obtained when 20gm of o2 reacts with12gm of carbon
Answers
Answer:
21:11
Explanation:
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Class 11
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>>Some Basic Concepts of Chemistry
>>Stoichiometry and Stoichiometric Calculations
>>By the reaction of carbon and oxygen, a
Question
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By the reaction of carbon and oxygen, a mixture of CO and CO
2
is obtained. What is the composition of the mixture by mass obtained when 20 g of O
2
reacts with 12 g of carbon?
Hard
Solution
verified
Verified by Toppr
Correct option is A)
The balanced chemical equations for the combustion reaction are as follows:
2xC+xO
2
→2xCO
yC+yO
2
→yCO
2
Total number of moles of C =2x+y
Total number of moles of oxygen = x+y
The molar masses of C and oxygen are 12 g/mol and 32 g/mol respectively.
12 g of C corresponds to 1 mole and 20 g of oxygen corresponds to
32
20
=0.625 moles.
Hence, 2x+y=1......(1)
and x+y=0.625......(2)
Substracting equation (2) from (1), we get
(2x+y)−(x+y)=1−0.625
x=0.375......(3)
Substituting equation (3) in equation (2), we get
0.375+y=0.625
y=0.250
The number of moles of CO formed are 2x=2(0.375)=0.75
The number of moles of CO
search-icon-header
Search for questions & chapters
search-icon-image
Class 11
>>Chemistry
>>Some Basic Concepts of Chemistry
>>Stoichiometry and Stoichiometric Calculations
>>By the reaction of carbon and oxygen, a
Question
Bookmark
By the reaction of carbon and oxygen, a mixture of CO and CO
2
is obtained. What is the composition of the mixture by mass obtained when 20 g of O
2
reacts with 12 g of carbon?
Hard
Solution
verified
Verified by Toppr
Correct option is A)
The balanced chemical equations for the combustion reaction are as follows:
2xC+xO
2
→2xCO
yC+yO
2
→yCO
2
Total number of moles of C =2x+y
Total number of moles of oxygen = x+y
The molar masses of C and oxygen are 12 g/mol and 32 g/mol respectively.
12 g of C corresponds to 1 mole and 20 g of oxygen corresponds to
32
20
=0.625 moles.
Hence, 2x+y=1......(1)
and x+y=0.625......(2)
Substracting equation (2) from (1), we get
(2x+y)−(x+y)=1−0.625
x=0.375......(3)
Substituting equation (3) in equation (2), we get
0.375+y=0.625
y=0.250
The number of moles of CO formed are 2x=2(0.375)=0.75
The number of moles of CO
2
formed are y=0.250
The molar masses of CO and CO
2
are 28 g/mol and 44 g/mol respectively.
The mass of CO formed is 0.75×28=21g
The mass of CO
2
formed is 0.250×44=11g.
Hence, the composition of the mixture is CO:CO
2
=21:11. is 0.250×44=11g.
Hence, the composition of the mixture is CO:CO
2
=21:11.