By remainder theorem find the remainder, when p(x)=2x³-11x²-4x+5, g(x)= 2x+1.
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g(x) = 2x + 1
0 = 2x +1
-1 = 2x
-1/2 = x
p(x) = 2x^3 - 11x^2 - 4x + 5
p(-1/2) = 2(-1/2)^3 - 11(-1/2)^2 - 4(-1/2) + 5
p(-1/2)= 2(-1/8) - 11(1/4) -2(-1) + 5
p(-1/2)= -1/4 -11/4 + 2 + 5
p(-1/2)= (-1-11)/4 + 7
p(-1/2)= -12/4 + 7
p(-1/2)= -3 + 7
p(-1/2)= 4
so the remainder is "4 "
0 = 2x +1
-1 = 2x
-1/2 = x
p(x) = 2x^3 - 11x^2 - 4x + 5
p(-1/2) = 2(-1/2)^3 - 11(-1/2)^2 - 4(-1/2) + 5
p(-1/2)= 2(-1/8) - 11(1/4) -2(-1) + 5
p(-1/2)= -1/4 -11/4 + 2 + 5
p(-1/2)= (-1-11)/4 + 7
p(-1/2)= -12/4 + 7
p(-1/2)= -3 + 7
p(-1/2)= 4
so the remainder is "4 "
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