Question

by remainder theorem ,find the remainder when p(x) is divided by g(x) p(x)= x^3-6x^2+2x-4,g(x)=1-3/2x​

Answer 1

Answer:

Step-by-step explanation:

Equate g(x) to 0.

So, 11-3/2x=0

11=3/2x

(11×2)/3=x

22/3=x

Now, put this value of x in p(x).

So, p(22/3)=(22/3)³-6×(22/3)²+2×22/3-4

=10648/27-6×484/9+44/3-4

=2224/27

Answer 2

Step-by-step explanation:

Given:

p(x) = x³ - 6x² + 2x - 4, g(x) = 1 - (3/2)x

To find:

the remainder when p(x) is divided by g(x) = ?

Solution:

g(x) = 0

⇒ 1 - (3/2)x = 0

⇒ x = 2/3

Remaimber = p(2/3)

= x³ - 6x² + 2x - 4

= (2/3)³ - 6(2/3)² + 2(2/3) - 4

= (8/27) - (24/9) + (4/3) - 4

Take the LCM of 3,9 and 27 is 27.

= (8 - 72 + 36 - 180)/27

= -136/27

Hence, the remainder is -136/27 when p(x) is divided by g(x).