by remainder theorem, find the remainder when p(x) is divided by g(x(
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Given,
p(x) = x³ -6x² +2x -4
g(x) = 1 - 3x/2
Zeros of p(x) is 2/3
p(2/3) = (2/3)³ -6(2/3)² +2(2/3) -4
= 8/27 -24/9 +4/3 -4
= 8-72+36-108/27
= -136/27
Therefore, R= -136/27
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