Question

by remainder theorem,find the remainder when p(y) is divided by g(y) 1. p(y)=y³-4y²-2y+6 and g(y)=1-3/4y​

Answer 1

Step-by-step explanation:

First we will find the zero of g(y),,

Equating g(y) with zero,,we get,,

g(y)=0

=>1-3/4y=0

=>3/4y=1

=>y=3/4

HENCE,,

p(y)=y³-4y²-2y+6

=>p(3/4)=(3/4)³-4(3/4)²-2(3/4)+6

=>p(3/4)=(27/64)-(9/4)-(3/2)+6

=>p(3/4)=(27-144-96+6)/64

=>p(3/4)=(33-240)/64

=>p(3/4)=-207/64 Ans...

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