by remainder theorem find when p (x) is divided by g x where iv) p x x^3-6x^2+4,g(x)=1-3/2
Answers
Answered by
1
Step-by-step explanation:
p(x)=x
3
−6x
2
+2x−4 and
g(x)=1−
2
3
x
1−
2
3
x=0
=>
2
3
x=1
=>x=
3
2
By, remainder theorem, the remainder when p(x) divided by g(x) is p(
3
2
)
Thus,
p(
3
2
)=(
3
2
)
3
−6(
3
2
)
2
+2(
3
2
)−4
=
27
8
−
9
6×4
+
3
4
−4
=
27
8
−
9
8
+
3
4
−4
=
27
8−24+36−108
=
27
−136
answer verified
veeresh
Similar questions