By Seeing Diagram what will be the perimeter of the Triangle ?
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Let PQ=QR=a cm
from right angled traingle hyp=PR= √2 a cm
given PR = 20 cm
hence √2 a = 20
a= 10√2 cm
perimeter = PQ+QR+PR
= a+a+√2 a
= 10√2+10√2+20
= 20√2+20
=20(√2+1)
= 20(1.414+1)
= 20(2.414)
= 48.28 cm
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