Question

BY SELLING 12 ORANGES FOR A RUPEE, A MAN LOSES 20%.HOW MANY FOR A RUPEE SHOULD HE SELL TO GET A AGAIN OF 20%

Answer 1

Hey,

CP of one orange= Rs. 1/12×1/0.8
SP= 1/12×1/0.8×1.2 = Rs. 1.8

So, For Re. 1= 【80 oranges】 ANSWER...

HOPE IT HELPS:-))

Answer 2

Answer: He should sell 8 oranges for a rupee to gain of 20%.

Step-by-step explanation:

Since we have given that

Let the cost price of 12 oranges be 'x'.

A man loses 20%.

Selling price of 12 oranges = Re. 1

According to question,

$1=80\%\ of\ x\\\\1=\frac{80}{100}\times x\\\\100\ paise=0.8\times x\\\\x=\frac{100}{0.8}=125\ paise$

He gets a gain of 20%.

$\frac{100+20}{100}\times 125\\\\=\frac{120}{100}\times 125\\\\=1.2\times 125\\\\=150\ paise$

So, For Re. 1, number of oranges he needed to sell,

$\frac{100}{150}\times 12\\\\=\frac{2}{3}\times 12\\\\=2\times 4\\\\=8$

Hence, He should sell 8 oranges for a rupee to gain of 20%.