Math, asked by rsravisharmaca, 5 months ago

By selling 180 oranges, a man lost the SP of 20 oranges. Find his loss percent. Had he purchased them for ₹270?What would have been the SP of one orange​

Answers

Answered by vinilvanshika15
1

Answer:

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Step-by-step explanation:

let SP of 1 orange=SP

and, CP of 1 orange=CP

then loss on 1 orange=CP-SP

a/c to the question

Total loss on 180 oranges=SP of 20 oranges

i.e 180(CP-SP)=20 SP

or, SP/CP=9/8

or, (SP-CP)/CP=1/8

Loss%=(SP-CP)/CP*100%=12.5%

Now, if CP=Rs 270

SP=87.5% of 270=Rs 236.25

Answered by ks5340030
3

Step-by-step explanation:

S.P of 1 =rupes 1

loss=sp of 1 =1*20=20

sp of 180 oranges=180

CP of 180 oranges 180-20=160

loss%=loss/CP*100

20/160*100=25%/2=12.5

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