Question

by selling 2 transistors for rupees 600 A shopkeeper gains 20% on one transistor and losses 20% on the other find c.p.of a transistor .total c.p. and total losses 20% on the other .profit or loss percent on the whole

Answer 1

1st transistors :
SP=600
Gain%=20%
CP={100×SP/100+gain%}
{100×600/100+20}
{100×600/120}
₹500

2nd transistors:
SP=600
loss%=20%
CP={100×SP/100-loss%}
{100×600|/100-20%}
{100×600/80}
₹750

Since;
Total CP=(500+750)
=₹1250
Total SP=(600+600)
=1200

So;
CP is greater than SP

loss=(1250-1200)
=₹50
loss%={50×100/1250}
=4% Ans.