Question

By selling 36 oranges, a vendor suffers a loss equal to the selling price of 4 oranges. Find his loss per cent. ​

Answer 1

AnswEr:-

Let us consider that Cost price of one orange = x rs.

Such that Cost price of 36 oranges = 36x.

And Selling Price of orange be s.

So, Selling Price of 36 oranges = 36x

$\rule{150}3$

★ Now, According to Question:-

loss = Selling Price of 4 oranges

We know that,

★ Loss = Cost Price - Selling Price

$:\implies\sf\; 4 s = 36 x - 36 s$

$:\implies\sf\;4 s + 36 s = 36 x$

$:\implies\sf\; 40s = 36 x$

So,

$:\implies\sf\;\dfrac{ 9x}{10}$

Now,

$:\implies\sf\; Loss\; \% = \dfrac{loss \times 100}{C.P}$

$:\implies\sf Loss\;\% = \dfrac{4s\times 100}{36 x}$

$:\implies\sf\; S = \dfrac{ 9\; x}{10}$

★ Putting the value of s

$:\implies\sf\;\dfrac{4s \times\; 9x \times\; 100}{36\; x}$

$:\implies\large\boxed{\sf{\red{ Loss = 10\;\% }}}$

$\rule{150}3$

Answer 2

Answer:

★Loss percent= 10% ★

Step-by-step explanation:

Given:

• After selling 36 orangesa vendor suffers a loss equal to the selling price of 4 oranges

To Find: Loss % in the whole transaction

Solution: Let the selling price of one orange be Rs x

→Then the selling price of 4 oranges= Rs 4x

A/q

→ Cost price of 36 oranges = 36x + 4x = 40x

→ Loss = Selling Price of 4 oranges= Rs 4x

† We know that Loss% = ( Loss/C.P x 100) %

Therefore

→ (4x / 40x) x 100 %

→ Loss% = 10%