By selling 4 article for rs. 1, a man profit 25%. had he sold 6 article per 1 rupee then what will be the loss percentage
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percentage factor(PF) is defined as (100+profit%) or (100-loss%)
Here
N1=4
N2=6
PF1=125%
PF2=?
PF is inversely proportional to no of articles
Therefore
N1/N2=PF2/PF1
or, 4/6=PF2/125
PF2=250/3(loss becoz less than 100)
loss%=100-250/3=50/3%(Ans.)
percentage factor(PF) is defined as (100+profit%) or (100-loss%)
Here
N1=4
N2=6
PF1=125%
PF2=?
PF is inversely proportional to no of articles
Therefore
N1/N2=PF2/PF1
or, 4/6=PF2/125
PF2=250/3(loss becoz less than 100)
loss%=100-250/3=50/3%(Ans.)
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