Question

by selling 7 oranges for Rs. 6.45 , Sambhu can make a profit of 29%. at what price per dozen must he sell them to gain 47%?

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

At 88.2 rupees price per dozen must he sell them to gain 47%.

Step-by-step explanation:

Given,Sambhu sold 7 oranges for Rs. 6.45.

So, Selling price of 7 oranges is 6.45 rupees.

By Unitary method, selling price of 1 orange is $\frac{6.45}{7} \: rupees$

It is also given that he made 29% profit.

So, 129% means $\frac{6.45}{7} \: rupees$

By Unitary method,1% means $\frac{6.45}{7 \times 129} \: rupees$

and 100% means

$\frac{6.45 \times 100}{129} \\ = \frac{645 \times 100}{100 \times 129} \\ = \frac{645}{129} \\ = 5 \: rupees$

We know cost price means 100%

Cost price of 1 orange is $5 \: rupees$

By Unitary method, cost of 12 orange is

$5 \times 12 \\ = 60 \: rupees$

So,100% means $60 \: rupees$

147% means

$\frac{ 60 \times 147}{100} \\ = \frac{6 \times 147}{10} \\ = \frac{3 \times 147}{5} \\ = \frac{441}{5} \\ = 88.2 \: rupees$

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