Question

By selling a computer table for 2400, Mayank loses 4%. At what price must he sell it to gain 12%.
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Answer 1

Step-by-step explanation:

Let CP be x

SP = 2400

Loss = 4/100 of CP

2400 = x - 4/100x

2400 = 96/100 x

x = 2400 × 100 /96

x= 2500

if profit = 12/100 of CP

then

SP = 2500 + (12/100)2500

SP = 2500 + 300

SP = 2800

Answer 2

Answer:

He must sell at Rs. 2800.

Given:

selling price of computer = Rs. 24,00

loss % = 4%

To find:

The price at must he sell computer to gain 12%.

Step-by-step explanation:

In case of loss,

C.P. > S.P  and

Loss = C.P. - S.P

It is given that, Mayank loses 4%

∴ C.P. > S.P

and percentage of loss = $\frac{loss}{C.P.} * 100$

Let the cost price of computer be Rs. x

⇒ Loss = C.P - S.P = x - 2400

loss % =  $\frac{x - 2400}{x} * 100$

$4 = \frac{x - 2400}{x}*100\\4x = (x - 2400)*100\\4x = 100x - 240000\\ 100x - 4x = 240000\\96x = 240000}\\x = \frac{240000}{96} \\x = 2500$

hence, the cost price of computer is Rs.2500.

Now,

in case of profit,

S.P. > C.P  and

Profit = S.P. - C.P

profit % = $\frac{profit}{C.P.} * 100$

As, to gain of 12%, the computer must at price higher than C.P.

Let the selling price of computer be Rs. y

⇒ Profit = S.P - C.P = y - 2400

loss % =  $\frac{y - 2500}{2500} * 100$

$12 = \frac{y - 2500}{2500}*100\\12*2500 = ({y - 2500)*100\\30000= 100y - 250000\\ 250000+30000 = 100y\\280000 = 100y}\\y = 2800$

hence, the selling price of computer is Rs.2800.

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