Question

By selling a refrigerator for rupees 5875 Mrs Chandan had a profit of 25% the cost price of a refrigerator​

Answer 1

See the attachment photo.

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Answer 2

Given

• Selling Price (S.P) = Rs.5875
• Profit (P%)= 25%

To Find

• Cost Price (C.P)

Solution

_________________________

We know that

$\boxed{\bf C.P = \dfrac{ 100× S.P }{ 100+ P\% } }$

• On Substituting The Values

$\: \: \: \: \: \: \implies\sf{C.P = \dfrac{ 100× 5875 }{ 100+ 25}}$

$\: \: \: \: \: \: \implies\sf{C.P = \dfrac{ 5875 00}{ 125}}$

$\: \: \: \: \: \: \implies\sf{C.P = 4700}$

Hence, Cost Price of refrigerator is Rs.4700.

• $\\\\\\\begin{gathered}\tiny\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{c } \bigstar\:\underline{\textbf{Profit and Loss Formulas :}}\\\\ \sf {\text{\footnotesize\textsf{}}} \:S.P. =\sf \bigg\lgroup\dfrac{100 + Profit \%}{100}\bigg\rgroup \times 100 \\ \\ \sf C.P. = \sf \dfrac{S.P. \times 100}{100 + Profit \%} \\ \\ \sf \:\:Profit = \sf \dfrac{Profit \% \times C.P.}{100} \\ \\ \sf \:Profit (gain) = S.P. - C.P. \\ \\ \end{array}}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}\end{gathered}$