Math, asked by sandhya7rani147, 1 day ago

by selling an article at 11/16 of its selling price a trader incurs a loss of 12% what is the profit percentage if the article is sold at 12% less than its actual selling price​

Answers

Answered by akankshadear
2

Hey you can do this way that is down

Step-by-step explanation:

Let the cost price of the article be Rs. X

According to question,

X × 125% = 2400

⇒ X × 5/4 = 2400

⇒ X = 1920

⇒ The cost price is Rs. 1920

Since, new selling price = Rs. 2160 and it is greater than 1920 (cost price of article)

⇒ Profit percentage = [(2160 – 1920)/1920] × 100

∴ Profit percentage is 25/2%

Answered by Harshitm077
0

Answer:

Profit percentage is 12.64%

Step-by-step explanation:

Let the actual SP be = 16x

He sells it at SP = 11/16 of 16x = 11x

He incurs loss of 12% by selling it at 11x.

So, 88% of CP = 11x

     88/100 of CP = 11x

     CP = 100x/8

Now, new SP = 88% of 16x

         new SP = 88/100 * 16x

         new SP = 1408x/100

Profit % = \frac{SP-CP}{CP}*100

             = \frac{1408x/100 - 100x/8}{100x/8}*100

             = 1264/100

             = 12.64%

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