Question

by selling of laptop for rupees 23000 a dealer on a profit of 15% . find it cost price​

Answer 1

Answer:

Let c. P. Of laptop be x. Gain =x*15%=x*15/100=3x/20. Gain=S.P- C. P

=23000-x=3x/20

23000=x+3x/20=23x/20

23000×20=23x

x=460000 /23

x=20000 , C. P=₹20000

explanation:

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Answer 2

Given :-

Selling Price = ₹23000

Profit % = 15%

To Find :-

The Cost Price of the laptop

Solution :-

Let the cost price be ₹ x

Total profit = 15% of CP

= 15% of x

$=\: {\dfrac{15}{100}}\: \times\: x$

$=\: {\dfrac{3x}{20}}$

SP = CP + Profit

$=\: x\: +\: {\dfrac{3x}{20}}$

$=\: {\dfrac{20x\: +\: 3x}{20}}$

$=\: {\dfrac{23x}{20}}$

But also given that SP is ₹23000

Therefore,

According to question :-

$23000\: =\: {\dfrac{23x}{20}}$

$\implies\: 23000\: \times\: 20\: =\: 23x$

$\implies\: x\: =\: {\dfrac{23000\: \times\: 20}{23}}$

$\implies\: x\: =\: \bold{20000}$

Therefore, the cost price of the laptop is ₹ 20,000